>>7319725PART 2/2

Well first of all you look at your original set of possible outcomes (reminder NN ,CN, NC, CC all equally likely, SUM MUST BE 100%) and you modify it to match the new conditions, namely 2 crits

leaving us with only (... ... ... CC, all equally likely, SUM MUST BE 100%).

There is only one possible outcome matching all given criteria and if only one outcome is possible the propability of that outcome is... well 100%

Now we do the exact same steps again, only this time with a different condition

> and at least one of them was a critAgain we have 4 possible outcomes (NN ,CN, NC, CC all equally likely, SUM MUST BE 100%) and again we sort out the outcomes that match the given condition (at least one crit), but this time we are left with 3 possible outcomes

(..., CN, NC, CC all equally likely, SUM MUST BE 100%). 3 possible outcomes, all equally likely, you dont need a masters degree in mathematics to figure out that thats a chance of 1/3 or 33,333...%.

Alright almost there

We were asked for the propability of him having 2 crits.

take a look at the set of possible outcomes again and see if you can figure out which of them match this condition, then add up their propabilities.

33,33% CN --> Nope

33,33% NC --> Nope

33,33% CC --> yes

-------------------

33,33% or exactly 1/3

there are 3 possible outcomes matching the condition "at least 1 crit", all equally likely (1/3) and within this set of 3 possible outcomes there is only one outcome matching the condition "2 crits", therefore

the propability of him having 2 crits is and will always be exactly 1/3

congratulations Anon !! you have now reached the mathematical understanding of a 5th grader